Posts filled under #dogstagram

Hello my friends 
Hope yo

Hello my friends Hope you are doing good ? Sorry we haven't been here because of the flu the faaaamous flue Have a good meal And a wonderfull day We Love You All Double tap if you like . . . Do you have a picture or a hilarious video of your Spitz? The world just needs to see his beauty Tag your friends who would love to see this beauty Send us pictures of your spitz dog DM or Tag Us @Spitz_DOG_Breeds Don't forget to share our page check out link in bio . . #Spitz_DOGS #Spitz #spitzofinstagram #spitzlovers #instaspitz #shiba #shibainu # #dog #shibastagram #puppy # #dogsofinstagram #shibalove #dogstagram #shibadog # # #shibalovers #inu #instadog # # #shibamania #cute #shibagram #doge #instashiba # #shibasofinstagram

I'm tilting my head becau

I'm tilting my head because I can't believe I have over EIGHT THOUSAND followers!!! I love each and every one of you. Thanks for watching me grow up. And shout out to the ones who have been with me from the very beginning! All your kind comments and messages always make me feel so loved! Y'all are THE BEST! . . #luckydog #oneluckyguy #headtilt #followerappreciation #iloveyou #fluffydogs #dogbandana #shihtzugram #shihtzu #shihtzusofinstagram #shihtzupuppy #shihtzu_feature #shihtzuofig #shihtzuoftheday #ilovemyshihtzu #shihtzucorner #shihtzunation #shihtzulove #dailydoggo #smalldogsofinstagram #ilovemydog #crazydogmom #furchild #dogstagram #dogoftheday #dailycute #marv #MarvMan

Do you remember Eddie? He

Do you remember Eddie? He is a recent rescue at 12 years old after spending 9 years in a sanctuary, and only shortly after being adopted his new mom found out he was blind. But that doesn't stop this tenacious boy! Using his senses of smell and hearing, he is able to navigate the agility equipment with his mom's help! #eddie #collie #sheltie #rescuedog #seniordog #bordercollie #shetlandsheepdog #bayareak9association #k9 #dogtraining #happydog #cute #fetch #rawfed #agility #protection #bestfriend #dog #offleash #puppygram #dogoftheday #dogsofinstagram #bayarea #puppy #workingdog #instadog #dogstagram #doglover

#Helados para #perros 
In

#Helados para #perros Ingredientes: 1 taza de #moras y #arndanos 2 yogurts 0% de grasa. Sin azcar 2 cucharadas de #miel Elaboracin: 1. Hacer un pur con las moras y los arndanos triturndolos con un tenedor. 2. Mezclar todos los ingredientes en un recipiente. 3. Verter la mezcla en una cubitera de hielo. 4. Dejarlo en el congelador durante al menos 4 horas. Portal: http://www.perricatessen.com/receta-helados-de-frutas-para-disfrutar-con-tu-perro/ #musalachichi #panchitocoladepincel #jackrussellterrier #instajackrussell #jackrussell #instajackrussellterrier #jrt #jrtofinstagram #jrtpost #jrtlove #jackrussellworld #instachihuaha #chihuahua #chihuahualove #instadog #instadogs #dogs #dogstagram #perrosdeinstagram #chihuahuasofinstagram #lovemydog #bestfriend #perrosfelices #perrodeldia

An extract on #dogstagram

First we start with a field k. In classical algebraic geometry, this field was always the complex numbers C, but many of the same results are true if we assume only that k is algebraically closed. We consider the affine space of dimension n over k, denoted An(k) (or more simply An, when k is clear from the context). When one fixes a coordinates system, one may identify An(k) with kn. The purpose of not working with kn is to emphasize that one "forgets" the vector space structure that kn carries. A function f : An A1 is said to be polynomial (or regular) if it can be written as a polynomial, that is, if there is a polynomial p in k[x1,...,xn] such that f(M) = p(t1,...,tn) for every point M with coordinates (t1,...,tn) in An. The property of a function to be polynomial (or regular) does not depend on the choice of a coordinate system in An. When a coordinate system is chosen, the regular functions on the affine n-space may be identified with the ring of polynomial functions in n variables over k. Therefore, the set of the regular functions on An is a ring, which is denoted k[An]. We say that a polynomial vanishes at a point if evaluating it at that point gives zero. Let S be a set of polynomials in k[An]. The vanishing set of S (or vanishing locus or zero set) is the set V(S) of all points in An where every polynomial in S vanishes. Symbolically, V ( S ) = { ( t 1 , , t n ) | p S , p ( t 1 , , t n ) = 0 } . {\displaystyle V(S)=\{(t_{1},\dots ,t_{n})|\forall p\in S,p(t_{1},\dots ,t_{n})=0\}.\,} A subset of An which is V(S), for some S, is called an algebraic set. The V stands for variety (a specific type of algebraic set to be defined below). Given a subset U of An, can one recover the set of polynomials which generate it? If U is any subset of An, define I(U) to be the set of all polynomials whose vanishing set contains U. The I stands for ideal: if two polynomials f and g both vanish on U, then f+g vanishes on U, and if h is any polynomial, then hf vanishes on U, so I(U) is always an ideal of the polynomial ring k[An]. Two natural questions to ask are: Given a subset U of An, when is U = V(I(U))? Given a set S of polynomials, when is S = I(V(S))? The answer to the first question is provided by introducing the Zariski topology, a topology on An whose closed sets are the algebraic sets, and which directly reflects the algebraic structure of k[An]. Then U = V(I(U)) if and only if U is an algebraic set or equivalently a Zariski-closed set. The answer to the second question is given by Hilbert's Nullstellensatz. In one of its forms, it says that I(V(S)) is the radical of the ideal generated by S. In more abstract language, there is a Galois connection, giving rise to two closure operators; they can be identified, and naturally play a basic role in the theory; the example is elaborated at Galois connection. For various reasons we may not always want to work with the entire ideal corresponding to an algebraic set U. Hilbert's basis theorem implies that ideals in k[An] are always finitely generated. An algebraic set is called irreducible if it cannot be written as the union of two smaller algebraic sets. Any algebraic set is a finite union of irreducible algebraic sets and this decomposition is unique. Thus its elements are called the irreducible components of the algebraic set. An irreducible algebraic set is also called a variety. It turns out that an algebraic set is a variety if and only if it may be defined as the vanishing set of a prime ideal of the polynomial ring. Some authors do not make a clear distinction between algebraic sets and varieties and use irreducible variety to make the distinction when needed.

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